Whole genome analysis for QTL/association enrichment
Running...
Version: Enrich S: beta v0.8
Data:
Number of age at sexual maturation traits:
2
Number of QTL / associations found:
27
Number of chromosomes where QTL / associations are found:
15
Chi-squared (χ2) test: are age at sexual maturation traits over-represented on some chromosomes?
Chromosomes
Total χ2
df
p-values
FDR *
Size of χ2
Chromosome 1
5.37778
14
0.9798296
0.9999999
Chromosome 2
0.71112
14
0.9999999
0.9999999
Chromosome 4
5.37778
14
0.9798296
0.9999999
Chromosome 5
0.04444
14
0.998329325823115
0.9999999
Chromosome 6
0.71112
14
0.9999999
0.9999999
Chromosome 9
0.71112
14
0.9999999
0.9999999
Chromosome 10
0.71112
14
0.9999999
0.9999999
Chromosome 11
1.60000
14
0.9999793
0.9999999
Chromosome 14
0.04444
14
0.998329325823115
0.9999999
Chromosome 15
0.71112
14
0.9999999
0.9999999
Chromosome 19
0.04444
14
0.998329325823115
0.9999999
Chromosome 21
0.04444
14
0.998329325823115
0.9999999
Chromosome 23
0.71112
14
0.9999999
0.9999999
Chromosome 25
0.71112
14
0.9999999
0.9999999
Chromosome 28
0.71112
14
0.9999999
0.9999999
Chi-squared (χ2) test: Which of the 2 age at sexual maturation traits are over-represented in the QTLdb
Traits
Total χ2
df
p-values
FDR *
Size of χ2
Female age at puberty
16.99999
1
3.738002e-05
7.476004e-05
Male age at puberty
9.99998
1
0.001565419
1.565419e-03
Correlations found between some of these traits for your reference
No correlation data found on these traits
Overall Test
Data
Chi'Square Test
Fisher's Exact Test
Number of chrom.:
15
χ2
=
18.222280
Number of traits:
2
df
=
14
Number of QTLs:
27
p-value
=
0.1968438
FOOT NOTE: * : FDR is short for "false
discovery rate", representing the expected proportion of type I errors. A type I
error is where you incorrectly reject the null hypothesis, i.e. you get a false
positive. It's statistical definition is FDR = E(V/R | R > 0) P(R > 0), where
V = Number of Type I errors (false positives); R = Number of rejected hypotheses.
Benjamini–Hochberg procedure is a practical way to estimate FDR.